OMG-OCUP2-FOUND100 Exam Questions - Navigate Your Path to Success

Correct : D

In UML sequence diagrams, a signal is typically represented as an asynchronous message without a return value. Asynchronous messages are often denoted with an open arrowhead, and they can represent the sending of a signal.

Looking at the diagram provided, 'p' is sent from 'v2[C]' to 'v3[B]' with an open arrowhead, which indicates that it is an asynchronous message. This fits the common representation of a signal, as it does not expect a response.

'A', 'B', and 'C' do not represent signals in the context of a sequence diagram: A) 'v' is not shown in the diagram; it might refer to a lifeline, which is not a signal. B) 'B' refers to a class or object type and not a message or signal. C) 'm' is represented as a synchronous message (as it has a return arrow), which is not typical for signals.

Therefore, the correct answer is:

D . p

Correct : B

In the second diagram provided, we see four messages: 'x', 'y', 'z', and 'p'. The vertical positioning of these messages indicates their order in time.

Option A states that 'Sending message x is the first occurrence that happens.' This could be true but is not necessarily always true, as there could be other messages or interactions before 'x' that are not shown in this part of the diagram.

Option B states that 'Sending message z will happen after receiving message x.' This is always true because the lifeline for 'v2[C]' shows the reception of 'x' before sending 'z'. In sequence diagrams, the vertical position indicates the sequence of events, and 'z' is clearly below 'x' on the 'v2[C]' lifeline.

Option C, 'Sending message y will happen before sending message z,' is not necessarily true because the messages 'y' and 'z' are sent by different lifelines, and there is no explicit ordering between them.

Option D, 'Sending message p will happen before receiving message y,' is not necessarily true as 'p' and 'y' involve different lifelines, and no ordering is specified between these interactions.

Therefore, the correct answer is:

B . Sending message z will happen after receiving message x.