The Oracle Java SE 17 Developer (1Z0-829) exam is a good choice and if the candidate manages to pass Oracle Java SE 17 Developer exam, he/she will earn Oracle Java Certification. Below are some essential facts for Oracle 1Z0-829 exam candidates:
Given the code fragment:
What is the result?
Correct : D
The answer is E because the code fragment creates a new Pet object with the name ''Dog'' and assigns it to the variable p. Then, it assigns p to p1. Next, it changes the name of p1 to ''Cat''. Then, it assigns p1 to p. Finally, it sets p to null and prints the name of p and p1. The output will be ''Cat'' and ''null'' because p is set to null and p1 still points to the Pet object with the name ''Cat''.
Given:
Which two modifications enable the code to print Open Close?
A)
B)
C)
D)
E)
Correct : B, E
The code given is a try-with-resources statement that declares a resource of type AutoCloseable. The resource is an anonymous class that implements the AutoCloseable interface and overrides the close() method. The code also has a print() method that prints the value of the variable s. The code is supposed to print ''Open Close'', but it does not compile because of two errors.
The first error is at line n1, where the anonymous class is missing a semicolon at the end of its declaration. This causes a syntax error and prevents the code from compiling. To fix this error, option B adds a semicolon after the closing curly brace of the anonymous class.
The second error is at line n2, where the print() method is called without an object reference. This causes a compilation error because the print() method is not static and cannot be invoked without an object. To fix this error, option E adds an object reference to the print() method by using the variable t.
Therefore, options B and E are correct and enable the code to print ''Open Close''.
